In data structure Hash, hash function is used to convert a string(or any other type) into an integer smaller than hash size and bigger or equal to zero. The objective of designing a hash function is to "hash" the key as unreasonable as possible. A good hash function can avoid collision as less as possible. A widely used hash function algorithm is using a magic number 33, consider any string as a 33 based big integer like follow:

hashcode("abcd") = (ascii(a) * 333+ ascii(b) * 332+ ascii(c) *33 + ascii(d)) % HASH_SIZE

                          = \(97\* 333+ 98 \* 332 + 99 \* 33 +100\) % HASH\_SIZE

                          = 3595978 % HASH\_SIZE

here HASH_SIZE is the capacity of the hash table (you can assume a hash table is like an array with index 0 ~ HASH_SIZE-1).

Given a string as a key and the size of hash table, return the hash value of this key.

Solution: Number will overflow if we use fomula directly.

public int hashCode(char[] key,int HASH_SIZE) {
    long hashcode = 0;
    for(int i = 0; i< key.length; i++) {
        hashcode += (Math.pow(33, key.length - i - 1) * (int)(key[i])) % HASH_SIZE;
    }
    hashcode = hashcode % HASH_SIZE;
    return hashcode;
}
public int hashCode(char[] key,int HASH_SIZE) {
    long sum = 0;
    for(int i = 0; i < key.length; i++) {
        sum = (33 * sum + (int)key[i]) % HASH_SIZE;
    }
    return (int)sum;
}

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